/sci/ - Science & Math

Yeah, L = √L • √L

>>12286246
yes

>>12286246
How’s the engineer degree going?

>>12286246
Sqrt[LC]*a/L
=(Sqrt[L]/L)*Sqrt[C]*a


just use exponent rule you fag. L^(1/2)/L, you do exponents and get 1/2 - 1 or -0.5=-1/2 which is 1/Sqrt[L].

so you get a*Sqrt[C]/Sqrt[L]

Assuming L>0. If L<0 and C<0, you have a sign change, don't you?

>>12286520
>>12286406
Cheers.
>>12286514
Kek, shit. This is for a mathematical modelling assignment though, actually ;).

>>12286246
Yes.
A root/it’s square = 1/that root
And you can split up square roots if it is multiplication

>>12286246
[math] a\sqrt{\frac{C}{L}} = a\sqrt{\frac{C}{L}} \sqrt{\frac{L}{L}} = a\sqrt{\frac{CL}{L^2}} = a\frac{\sqrt{CL}}{\sqrt{L^2}} = \frac{\sqrt{LC}a}{L} [/math]

How's high school?

>>12286977
Man I haven't seen this surds shit SINCE high school, thanks for the throwback.
I remember them teaching us that trick to get rid of square root numerators.

>>12286246
you have to be 18 to post here

>>12287527
Bro you got me

>-1
>Rationalize the denominator!

its clearest if you let b = sqrt(L), such that sqr(bC)a/b^2 = sqrt(C) * a/sqrt(L) = a * sqrt(C/L)

[math]Take a=\sqrt{x} \\ Then \frac{x}{\sqrt{x}} = \frac{a^2}{a} = a = \sqrt{x}[/math]
Why doesn't that work?

>>12286989
It’s not just a trick anon, this should be second nature to you

>>12289573
To be honest yeah I do fully remember it, I hadn't slept for over 24 hours when I made this post lmao.
Having said that though, I can't recall using the technique in the last two years of my studies - though I can see why its just a basically useful algebra skill.
And yes I am peabrain engineer student but I also have a degree in comp sci and minor in math so you'd expect it to have popped up somewhere in that time.

>>12289587
Glad to have you on board anon